3x^2+800x=-20000

Solution for 3x^2+800x=-20000 equation:

3x^2+800x=-20000

We move all terms to the left:

3x^2+800x-(-20000)=0

We add all the numbers together, and all the variables

3x^2+800x+20000=0

a = 3; b = 800; c = +20000;
Δ = b2-4ac
Δ = 8002-4·3·20000
Δ = 400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{400000}=\sqrt{40000*10}=\sqrt{40000}*\sqrt{10}=200\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-200\sqrt{10}}{2*3}=\frac{-800-200\sqrt{10}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+200\sqrt{10}}{2*3}=\frac{-800+200\sqrt{10}}{6}
$